0=94+6x-8x^2

Solution for 0=94+6x-8x^2 equation:

0=94+6x-8x^2

We move all terms to the left:

0-(94+6x-8x^2)=0

We add all the numbers together, and all the variables

-(94+6x-8x^2)=0

We get rid of parentheses

8x^2-6x-94=0

a = 8; b = -6; c = -94;
Δ = b2-4ac
Δ = -62-4·8·(-94)
Δ = 3044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3044}=\sqrt{4*761}=\sqrt{4}*\sqrt{761}=2\sqrt{761}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{761}}{2*8}=\frac{6-2\sqrt{761}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{761}}{2*8}=\frac{6+2\sqrt{761}}{16}
$